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00:00 - 00:59 | prove that a + b whole cube equal to 8 cube plus b cube plus 3GB and Bracket a + b of a stressful for providing this we will take the left hand side and left inside we have given 30 + b whole cube and we can also write it as a + b and b + b + b this is the form of a + b whole cube because in the multiplication power should be added so well with the power of this one power of this one and power of this also been so when we do the multiplication then Power Will even placement placement it will be power 3 so we can also that it is a + b whole cube as this can also write it has a + b in multiplication power will be added in oneplus one it will be a + b whole square and undirected is a + b then further we know the formula of the a + b whole square that is a square |

01:00 - 01:59 | + b square + 2 AV and under packet it is a plus bi Subah after the multiplication of the a place with this whole time and it will be multiplication with v and that is a square B square + 2 AV in place we have to multiply with this whole time that is a square + b square + 2 AV so many simplify this and it will be a into a square it is a cube + 8 is a b square + 1 into a visit to is this will be a square and a into b square it is DQ entry into 28032 every square then find the be simplified this and we will get a cube plus b cube plus b square and square it is a square and |

02:00 - 02:59 | to a square b square B is 3 square B then further simplify this this is a cube plus b cube plus B can take a common as 83 ab the remaining in the bracket is in place so this is our right and sign hands group thank you |

**Definition of algebraic expressions**

**Operations on algebric expressions - Addition, Subtraction, Multiplication and Division**

**Some Important Identities - (i) `(a+b)^2 = a^2 + 2ab + b^2` (ii) `(a-b)^2 = a^2 - 2ab + b^2`**

**Important Identity - `(a-b)(a+b) = a^2 - b^2`**

**Important Identitiy `(x+a)(x+b) = x^2+(a+b)x+ab`**

**Expand each of the following (i) `(2x+5y)^2` (ii) `(x-3y)^2` (iii) `(x+5)(x-3)`**

**Evaluate each of the following by using Identities - (i) 103 x 97 (ii) 103 x 103 (iii) 97 x 97 (iv) 105 + 106**

**Simplify : `(a-1/a)(a+1/a)(a^2+1/a^2)(a^4+1/a^4)(a^8+1/a^8)`**

**If `x+1/x = 4`; Find (i) `x^2+1/x^2` (ii) `x^4 + 1/x^4`**

**If `x^2+1/x^2` = 5 is given then find the value of (i) `x+1/x` (ii) ` x-1/x`**